4^(n)*4^(2n-9)=64

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Solution for 4^(n)*4^(2n-9)=64 equation: 



4^(n)*4^(2n-9)=64

We move all terms to the left:

4^(n)*4^(2n-9)-(64)=0

Wy multiply elements

16n^2(2-64=0

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